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3.5=-0.5x^2+8
We move all terms to the left:
3.5-(-0.5x^2+8)=0
We get rid of parentheses
0.5x^2-8+3.5=0
We add all the numbers together, and all the variables
0.5x^2-4.5=0
a = 0.5; b = 0; c = -4.5;
Δ = b2-4ac
Δ = 02-4·0.5·(-4.5)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3}{2*0.5}=\frac{-3}{1} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3}{2*0.5}=\frac{3}{1} =3 $
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